Given below are two statements:

Statement I: Aluminium is more electropositive than thallium as the standard electrode potential value of E$$^\circ_{Al^{3+}/Al}$$ is negative and E$$^\circ_{Tl^{3+}/Tl}$$ is positive.

Statement II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms Al$$^{3+}$$ ion.

In the light of the above statements, choose the correct answer from the options given below:

For Statement I:

Standard electrode potential of Aluminium:

$$E_{Al^{3+}/Al}^{\circ}=-1.66\ V$$

Standard electrode potential of Thallium:

$$E_{Tl^{3+}/Tl}^{\circ}=+1.25\ V$$

More negative the reduction potential, greater is the tendency to lose electrons.

Hence, Aluminium loses electrons more easily than Thallium.

Therefore, Aluminium is more electropositive than Thallium.

Hence, Statement I is Correct.

For Statement II:

Boron has very high ionization enthalpy values.

Sum of first three ionization enthalpies of Boron is very high compared to Aluminium.

Therefore, removal of three electrons from Boron is difficult.

Hence, Boron does not form $$B^{3+}$$ ions and mainly forms covalent compounds

Hence, Statement II is Correct.

Therefore, Option A is Correct