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A car reached a distance of 340 km in 4 hours .It travels some distance at a speed of 90 kmph and the remaining at speed of 60 kmph,then distance travelled with speed of 60 kmph , in kilometers, is
Let the distance travelled at 60 kmph be d km
Hence, distance travelled at 90 kmph be (340-d) km.
Hence, $$\frac{d}{60}+\frac{340-d}{90}=4$$
Solving this, we get d = 40 km
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