The sum of oxidation state of the metals in Fe(CO)$$_5$$, VO$$^{2+}$$ and WO$$_3$$ is _____.

We need to find the sum of oxidation states of the metals in $$Fe(CO)_5$$, $$VO^{2+}$$, and $$WO_3$$.

$$Fe(CO)_5$$ (Iron pentacarbonyl):

$$CO$$ is a neutral ligand with zero charge.

Therefore, the oxidation state of Fe = 0.

$$VO^{2+}$$ (Vanadyl ion):

Let the oxidation state of V be $$x$$.

Oxygen has an oxidation state of $$-2$$.

$$x + (-2) = +2$$

$$x = +4$$

The oxidation state of V = +4.

$$WO_3$$ (Tungsten trioxide):

Let the oxidation state of W be $$y$$.

$$y + 3(-2) = 0$$

$$y = +6$$

The oxidation state of W = +6.

The sum of oxidation states:

$$0 + 4 + 6 = 10$$

The sum of the oxidation states of the metals is 10.