The major product expected from the following reaction is:

The given compound contains a carboxylic acid and a primary alcohol group positioned suitably for an intra-molecular reaction.

In the presence of $$HCL(g)/CCl_4$$, a strongly acidic and non-aqueous medium, the carboxylic acid group gets activated, facilitating intramolecular esterification reaction with the neighboring alcohol group, resulting in the formation of a five-membered lactone ring.

The amide and the phenolic groups remain unaffected under the given conditions. 

Thus, the major product is option C.