Question 57
Let x be the greatest number which when divides 6475, 4984 and 4132, the remainder in each case is the same. What is the sum of digits of x a?
Solution
Let x be the greatest number which when divides 6475, 4984 and 4132, the remainder in each case is the same,then
6475 - 4984 = 1491
4984 - 4132 = 852
6475 - 4132 = 2343
Required Number = HCF of 1491, 852 and 2343
i.e; 213 is the HCF
Sum of the Digits = 2 + 1 + 3 = 6
Hence, Option D is correct.
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