Question 57

Let x be the greatest number which when divides 6475, 4984 and 4132, the remainder in each case is the same. What is the sum of digits of x a?

Solution

Let x be the greatest number which when divides 6475, 4984 and 4132, the remainder in each case is the same,then

6475 - 4984 = 1491

4984 - 4132 = 852

6475 - 4132 = 2343

Required Number = HCF of 1491, 852 and 2343

i.e; 213 is the HCF

Sum of the Digits = 2 + 1 + 3 = 6

Hence, Option D is correct.

Create a FREE account and get: