The full marks for a paper is 300. The break-up of the marks into theory (X), practical (Y) and project (Z), which are the three components of evaluation is 6 : 5 : 4. In order to pass one has to score at least 40%, 50% and 50% respectively in X, Y, Z and 60% in aggregate. The marks scored by four students A, B, C and D are shown in the given Bar Graph.
Question 57
Arrange the students B, C and D accordingto the ascending order of the aggregate marks scored by them.
Solution
Aggregate marks of B = $$\frac{(50+50+30)}{300}\times100$$=43.33%
Aggregate marks of C = $$\frac{(70+80+60)}{300}\times100$$=70%
Aggregate marks of D = $$\frac{(80+70+30)}{300}\times100$$=60%
