[Solved] The electrode potential of the following half cell at 298 K X|X^{2+}(0.001M)||Y^{2+}(0.01M)|Y is ______ \\times 10^{-2} V (Nearest integer) Given: E^0_{X^{2+}/X} = -2.36 V E^0_{Y^{2+}/Y} = +0.36 V \\frac{2.303 RT}{F} = 0.06 V - - NTA JEE Main 30th January 2023 Shift 2