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Aryl fluorides are compounds where a fluorine atom is directly bonded to an aromatic ring. They can be prepared from arene diazonium chloride (Ar-N₂⁺ Cl⁻) using specific reagents that replace the diazonium group (-N₂⁺) with fluorine.
Let's evaluate each option:
Option A: $$HBF_4/\Delta$$
This method is known as the Schiemann reaction. The arene diazonium chloride reacts with fluoroboric acid (HBF₄) to form arene diazonium fluoroborate. Upon heating (Δ), this salt decomposes to yield the aryl fluoride, boron trifluoride, and nitrogen gas. The reactions are:
Step 1: $$\text{Ar-N}_2^+ \text{Cl}^- + \text{HBF}_4 \rightarrow \text{Ar-N}_2^+ \text{BF}_4^- + \text{HCl}$$
Step 2: $$\text{Ar-N}_2^+ \text{BF}_4^- \rightarrow \text{Ar-F} + \text{BF}_3 + \text{N}_2$$
This is a standard and reliable method for preparing aryl fluorides.
Option B: $$HBF_4/\text{NaNO}_2, \text{Cu}, \Delta$$
Here, NaNO₂ is used for diazotization, but the starting material is already arene diazonium chloride, so diazotization is unnecessary. Adding copper (Cu) and heat (Δ) suggests a Sandmeyer-like reaction, but Sandmeyer is typically used for chlorine, bromine, or cyanide, not fluorine. Copper(I) fluoride is unstable and not suitable for fluorination. Moreover, HBF₄ is used in the Schiemann reaction without NaNO₂ or copper. Thus, this combination is incorrect for aryl fluoride synthesis.
Option C: $$\text{CuF}/\text{HF}$$
Copper(I) fluoride (CuF) is unstable and not commonly used in organic synthesis. HF alone can be hazardous and is typically used for hydrofluorination or in other contexts, but not for converting diazonium salts to aryl fluorides. There is no standard reaction using CuF/HF for this purpose.
Option D: $$\text{Cu}/\text{HF}\ 0$$
The "0" likely indicates a temperature of 0°C, but this combination is unclear. Copper metal (Cu) and hydrofluoric acid (HF) do not form a known reagent for replacing the diazonium group with fluorine. No standard method uses Cu/HF at any temperature for aryl fluoride preparation.
After evaluating all options, only Option A ($$HBF_4/\Delta$$) correctly describes the Schiemann reaction, which is a specific and effective method for preparing aryl fluorides from arene diazonium chloride.
Hence, the correct answer is Option A.
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