When a 60 W electric heater is immersed in a gas for 100 s in a constant volume container with adiabatic walls, the temperature of the gas rises by 5°C. The heat capacity of the given gas is JK$$^{-1}$$ (Nearest integer)

A 60 W electric heater was immersed in a gas for 100 s in an adiabatic, constant-volume container, causing the temperature to rise by 5°C.

First the total heat supplied by the heater is calculated using the relation $$Q = P \times t = 60 \times 100 = 6000 \text{ J}$$.

Because the container is adiabatic, all the supplied heat goes into raising the gas temperature, so $$Q = C \times \Delta T$$, where $$C$$ is the heat capacity of the gas.

Solving for the heat capacity gives $$C = \frac{Q}{\Delta T} = \frac{6000}{5} = 1200 \text{ JK}^{-1}$$.

The heat capacity of the gas is 1200 JK$$^{-1}$$.