A person has to travel from point B in certain time. Travelling at a speed of 5 kmph he reaches 48 minutes late and while travelling at a speed of 8 kmph he reaches 15 minutes early. What is the distance from point A to point B?
Let the distance between A and B be 'd' km and time taken be 't' hrs.
In both the cases, distance travelled is the same.
Distance = Speed $$\times$$ Time
Case (i) Time taken = 48 min late = (t + 0.8) hrs
$$d = 5 \times (t + 0.8)$$
Case (ii) Time taken = 15 min early = (t - 0.25) hrs
$$d = 8 \times (t - 0.25)$$
On equating them, we get
5t + 4 = 8t - 2
t = 2
Distance, d = 5 (2 + 0.8) = 14 km
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