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For the reaction $$N_2O_4(g) \rightleftharpoons 2NO_2(g)$$, $$K_p = 0.492$$ atm at $$300$$ K. $$K_c$$ for the reaction at same temperature is _______ $$\times 10^{-2}$$. (Given: $$R = 0.082$$ L atm mol$$^{-1}$$ K$$^{-1}$$)
Correct Answer: 2
$$K_p = K_c(RT)^{\Delta n}$$. $$\Delta n = 2-1 = 1$$.
$$K_c = K_p/(RT) = 0.492/(0.082 \times 300) = 0.492/24.6 = 0.02 = 2 \times 10^{-2}$$.
The answer is $$\boxed{2}$$.
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