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4 g equimolar mixture of NaOH and Na$$_2$$CO$$_3$$ contains xg of NaOH and yg of Na$$_2$$CO$$_3$$. The value of x is ___g. (Nearest integer)
Correct Answer: 1
In an equimolar mixture, both NaOH and Na$$_2$$CO$$_3$$ are present in equal numbers of moles. Let the number of moles of each compound be $$n$$. The total mass of the mixture is 4 g:
$$n \times M_{\text{NaOH}} + n \times M_{\text{Na}_2\text{CO}_3} = 4 \text{ g}$$
The molar masses are: NaOH = 23 + 16 + 1 = 40 g mol$$^{-1}$$, and Na$$_2$$CO$$_3$$ = 2(23) + 12 + 3(16) = 106 g mol$$^{-1}$$.
$$n(40 + 106) = 4$$
$$n = \frac{4}{146} = 0.02740 \text{ mol}$$
The mass of NaOH in the mixture is:
$$x = n \times 40 = \frac{4}{146} \times 40 = \frac{160}{146} \approx 1.096 \text{ g}$$
Rounding to the nearest integer, the value of $$x$$ is $$\mathbf{1}$$ g.
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