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Zinc reacts with hydrochloric acid to give hydrogen and zinc chloride. The volume of hydrogen gas produced at STP from the reaction of 11.5 g of zinc with excess HCl is L (Nearest integer)
(Given: Molar mass of Zn is 65.4 g mol$$^{-1}$$ and Molar volume of H$$_2$$ at STP = 22.7 L)
Correct Answer: 4
The balanced equation for the reaction:
$$ Zn + 2HCl \rightarrow ZnCl_2 + H_2 $$
Moles of zinc:
$$ n_{Zn} = \frac{11.5}{65.4} = 0.1758 \text{ mol} $$
From the stoichiometry, 1 mole of Zn produces 1 mole of H$$_2$$:
$$ n_{H_2} = 0.1758 \text{ mol} $$
Volume of H$$_2$$ at STP:
$$ V = n \times V_m = 0.1758 \times 22.7 = 3.99 \approx 4 \text{ L} $$
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