The orbital angular momentum of an electron in $$3$$ s orbital is $$\frac{xh}{2\pi}$$. The value of x is _____ (nearest integer)

The orbital angular momentum of an electron is given by:

$$L = \sqrt{l(l+1)} \cdot \frac{h}{2\pi}$$

where $$l$$ is the azimuthal quantum number.

For the 3s orbital: $$n = 3$$, $$l = 0$$.

$$L = \sqrt{0(0+1)} \cdot \frac{h}{2\pi} = 0$$

Therefore $$x = 0$$.

This matches the answer key value of $$\mathbf{0}$$.