In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer a: if x > y
Give answer b: if x ≥ y
Give answer c: if x < y
Give answer d: if x ≤ y
Give answer e: if x = y or the relationship between x and y cannot be established.
I. $$2x^{2}-13x+18=0$$
II. $$y^{2}-7y+12=0$$
I. $$2x^{2} - 13x + 18 = 0$$
=> $$2x^2 - 4x - 9x + 18 = 0$$
=> $$2x (x - 2) - 9 (x - 2) = 0$$
=> $$(2x - 9) (x - 2) = 0$$
=> $$x = 2 , \frac{9}{2}$$
II. $$y^{2} - 7y + 12 = 0$$
=> $$y^2 - 4y - 3y + 12 = 0$$
=> $$y (y - 4) - 3 (y - 4) = 0$$
=> $$(y - 4) (y - 3) = 0$$
=> $$y = 3 , 4$$
$$\therefore$$ No relation can be established.
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