In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer a: if x > y
Give answer b: if x ≥ y
Give answer c: if x < y
Give answer d: if x ≤ y
Give answer e: if x = y or the relationship between x and y cannot be established.
I. $$2x^{2}-13x+21=0$$
II.$$3y^{2}-14y+15=0$$
I. $$2x^{2} - 13x + 21 = 0$$
=> $$2x^2 - 6x - 7x + 21 = 0$$
=> $$2x (x - 3) - 7 (x - 3) = 0$$
=> $$(2x - 7) (x - 3) = 0$$
=> $$x = 3 , \frac{7}{2}$$
II. $$3y^{2} - 14y + 15 = 0$$
=> $$3y^2 - 9y - 5y + 15 = 0$$
=> $$3y (y - 3) - 5 (y - 3) = 0$$
=> $$(3y - 5) (y - 3) = 0$$
=> $$y = 3 , \frac{5}{3}$$
$$\therefore x \geq y$$
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