Question 52

For a certain reaction at 300 K, K = 10, then $$\Delta G°$$ for the same reaction is - ______ $$\times$$ $$10^{-1}$$ $$kJ mol^{-1}$$. (Given $$R = 8.314 \text{ J K}^{-1} \text{mol}^{-1}$$)

Correct Answer: 57

$$\Delta G^\circ = -2.303 \cdot R \cdot T \cdot \log_{10}(K)$$

$$\Delta G^\circ = -2.303 \times 8.314 \times 300 \times 1$$

$$\Delta G^\circ = -5744.14 \text{ J mol}^{-1}$$

To convert Joules to kilojoules, divide by $$1000$$:

$$\Delta G^\circ = -5.74414 \text{ kJ mol}^{-1}$$

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