Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 51
The value of $$\frac{1 - 2 \sin^2 \theta \cos^2 \theta}{\sin^4 \theta + \cos^4 \theta} - 1$$ is:
Solution
$$\frac{1 - 2 \sin^2 \theta \cos^2 \theta}{\sin^4 \theta + \cos^4 \theta} - 1$$
=Â $$\frac{1 - 2 \sin^2 \theta \cos^2 \theta -Â \sin^4 \theta - \cos^4 \theta}{\sin^4 \theta + \cos^4 \theta}$$
= $$\frac{1 - (sin^2 \theta + \cos^2 \theta)^2 }{\sin^4 \theta + \cos^4 \theta}$$
= $$\frac{1 - 1}{\sin^4 \theta + \cos^4 \theta}$$ = 0
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
