Match List - I with List - II.

Choose the correct answer from the options given below :

Number of atoms $$=\left(\frac{mass}{molar\ mass}\right)\times\ N_A\times\ Atomicity$$

where,

Atomicity is number of atoms

$$N_A$$ is Avogadro's Number 

A. 1.8mg of water $$H_{2}O$$

Atoms $$=\left(\frac{1.8\times\ 10^{-3}}{18}\right)\times\ N_A\times\ 3$$

$$=3\times\ 10^{-4}\times\ N_A$$

(III)

B. 9.8 mg Sulphuric Acid $$H_{2}SO_4$$

Atoms $$=\left(\frac{9.8\times\ 10^{-3}}{98}\right)\times\ N_A\times\ 7$$

$$=7\times\ 10^{-4}\times\ N_A$$

(IV)

C. 1.8 mg Carbon $$(C)$$

Atoms $$=\left(\frac{1.8\times\ 10^{-3}}{12}\right)\times\ N_A\times\ 1$$

$$=1.5\times\ 10^{-4}\times\ N_A$$

(II)

D. 5.85 MG Salt $$(NaCl)$$

Atoms $$=\left(\frac{5.8\times\ 10^{-3}}{58.5}\right)\times\ N_A\times\ 2$$

$$=2\times\ 10^{-4}\times\ N_A$$

(I)

Therefore, Option C is correct