In an examination in which the full marks were 500, A scored 25% more marks than B, B scored 60% more marks than C and C scored 20% less marks than D. If A scored 80% marks, then the percentage of marks obtained by D is:
Given, Total marks = 500
A scored 80% marks in the examination
$$\Rightarrow$$Â A =Â $$\frac{80}{100}\times500$$ = 400
A scored 25% more marks than B
$$\Rightarrow$$Â A =Â $$\frac{125}{100}$$B
$$\Rightarrow$$Â 400 =Â $$\frac{125}{100}$$B
$$\Rightarrow$$Â 400 = $$\frac{5}{4}$$B
$$\Rightarrow$$Â B = 320
B scored 60% more marks than C
$$\Rightarrow$$Â B =Â $$\frac{160}{100}$$C
$$\Rightarrow$$Â 320 =Â $$\frac{160}{100}$$C
$$\Rightarrow$$Â C = 200
C scored 20% less marks than D
$$\Rightarrow$$Â C =Â $$\frac{80}{100}$$D
$$\Rightarrow$$Â 200 =Â $$\frac{80}{100}$$D
$$\Rightarrow$$Â D = 250
$$\therefore\ $$Percentage of marks obtained by D =Â $$\frac{250}{500}$$ = 50%
Hence, the correct answer is Option C
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