Question 51

For hydrogen atom, the orbital/s with lowest energy is/are:$$\text{ (A) } 4s \text{ (B) } 3p_x \text{ (C) } 3d_{x^2-y^2} \text{ (D) } 3d_{z^2} \text{ (E) } 4p_z$$ Choose the correct answer from the options given below:

For hydrogen atom, energy depends only on n (principal quantum number), not on l.

3p, 3d all have n=3 (same energy). 4s has n=4 (higher energy).

So 3px, 3d_{x²-y²}, 3d_{z²} all have the lowest energy among the options (n=3).

The correct answer is Option 1: (B), (C) and (D) only.

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