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The equivalent resistance between the points A and B in the following circuit is $$\frac{x}{5}$$Ω. The value ofx is________.
Correct Answer: 21
step 1: assume currents
Let total current from source = i
At node A, current splits:
top branch =$$i_1$$
bottom branch = $$i-i_1$$
step 2: apply loop equation (top loop)
$$6i_1+3(2i_1-i)=3(i-i_1)$$
simplify:
$$6i_1+6i_1-3i=3i-3i_1$$
$$12i_1-3i=3i-3i_1$$
$$15i_1=6i\Rightarrow i_1=\frac{2}{5}i$$step 3: apply KVL for left path
$$3(i-i_1)+6i_1=1$$
substitute $$i_1$$:
$$3\left(i-\frac{2}{5}i\right)+6\left(\frac{2}{5}i\right)=1$$
$$3\left(\frac{3}{5}i\right)+\frac{12}{5}i=1$$
$$\frac{9}{5}i+\frac{12}{5}i=1$$
$$\frac{21}{5}i=1\Rightarrow i=\frac{5}{21}$$step 4: equivalent resistance
$$R_{eq}=Vi=\frac{1}{\frac{5}{21}}=\frac{21}{5}Ω$$
given form:
$$R_{eq}=\frac{x}{5}\Rightarrow x=21$$Create a FREE account and get:
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