Let $$(x_0, y_0)$$ be the solution of the following equations
$$(2x)^{\ln 2} = (3y)^{\ln 3}$$
$$3^{\ln x} = 2^{\ln y}$$
Then $$x_0$$ is

A

$$\frac{1}{6}$$

B

$$\frac{1}{3}$$

C

$$\frac{1}{2}$$

D

$$6$$