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Question Stem
Three numbers are chosen at random, one after another with replacement, from the set $$S = \left\{1, 2, 3, …, 100 \right\}$$. Let $$p_1$$ be the probability that the maximum of chosen numbers is at least 81 and $$p_2$$ be the probability that the minimum of chosen numbers is at most 40.
The value of $$\frac{625}{4} p_1$$ is .........
Correct Answer: 76.10 - 76.40
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