The sum of the squares of three numbers is 336 and the ratio of the first and the second as also of the second and the third is 1 : 2. Then find the difference of third and first number?
Let the number be x, 2x, 4x
According to the question,
$$x^2+4x^2+16x^2=336$$
$$21x^2=336$$
$$x^2=16$$
$$x=4$$
Required difference = 16 - 4= 12
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