Perpendiculars are drawn from points on the line $$\frac{x + 2}{2} = \frac{y + 1}{-1} = \frac{z}{3}$$ to the plane x + y + z = 3. The feet of perpendiculars lie on the line

A

$$\frac{x}{5} = \frac{y - 1}{8} = \frac{z - 2}{-13}$$

B

$$\frac{x}{2} = \frac{y - 1}{3} = \frac{z - 2}{-5}$$

C

$$\frac{x}{4} = \frac{y - 1}{3} = \frac{z - 2}{-7}$$

D

$$\frac{x}{2} = \frac{y - 1}{-7} = \frac{z - 2}{5}$$