Given below are two statements: Statement (I): The $$-NH_2$$ group in Aniline is ortho and para directing and a powerful activating group. Statement (II): Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation). In the light of the above statements, choose the most appropriate answer from the options given below:

Statement I: The $$-NH_2$$ group in aniline is ortho and para directing and a powerful activating group.

Analysis: The $$-NH_2$$ group is indeed an ortho/para director due to the lone pair on nitrogen which donates electron density to the ring via resonance. It is a powerful activating group — it strongly activates the benzene ring toward electrophilic aromatic substitution.

Statement I is correct.

Statement II: Aniline does not undergo Friedel-Craft's reaction (alkylation and acylation).

Analysis: Aniline does NOT undergo Friedel-Craft's reaction because the lone pair on the $$-NH_2$$ group coordinates with the Lewis acid catalyst ($$AlCl_3$$), forming a salt. This effectively deactivates the catalyst and also makes the ring electron-poor (as the nitrogen lone pair is no longer available for resonance with the ring).

Statement II is correct.

Conclusion: Both statements are correct.

The answer is Option A: Both Statement I and Statement II are correct.