Question 48
A tap can empty a tank in one hour. A second tap can empty it in 30 min If both the taps operate simultaneously, how much time is needed to empty the tank ?
Solution
1 minute work of tap A = $$\frac{1}{60}$$
1 minute work of tap B = $$\frac{1}{30}$$
=> (A + B)'s 1 minute work = $$\frac{1}{60} + \frac{1}{30}$$
= $$\frac{1 + 2}{60} = \frac{3}{60}$$
= $$\frac{1}{20}$$
$$\therefore$$ Time taken by (A + B) to empty the tank = 20 min
Get AI Help?
Create a FREE account and get:
- Banking Quant Shortcuts PDF
- Free Banking Study Material - (15000 Questions)
- 135+ Banking previous papers with solutions PDF
- 100+ Online Tests for Free
