Consider the following reaction
Propanal + Methanal $$\xrightarrow{(i)$$ dil. NaOH $$}{\xrightarrow{(ii) \Delta \; (iii)$$ NaCN $$\; (iv) \; H_3O^+}}$$ Product B (C$$_5$$H$$_8$$O$$_3$$)
The correct statement for product B is. It is

A

optically active and adds one mole of bromine

B

racemic mixture and is neutral

C

racemic mixture and gives a gas with saturated NaHCO$$_3$$ solution

D

optically active alcohol and is neutral