Pankaj has done 1/2 of a job in 12 days, Sainath completes the rest of the job in 6 days. In how many days can they together do the job?

Let total work to be done = 24 units

Pankaj has done 1/2 of a job i.e. $$\frac{24}{2} = 12$$ units in 12 days

=> Pankaj's efficiency = $$\frac{12}{12} = 1$$ unit/day

Work left = 24 - 12 = 12 units which is done by Sainath in 6 days

=> Sainath's efficiency = $$\frac{12}{6} = 2$$ units/day

Pankaj and Sainath 1 day's work = $$1 + 2 = 3$$ units/day

$$\therefore$$ Time taken by them together to complete the work = $$\frac{24}{3} = 8$$ days

=> Ans - (C)