Match List - I with List - II.

Choose the correct answer from the options given below :

A) Since Cr is in +3 oxidation state, the electronic configuration is 4s2 3d3. That means 3 unpaired electrons are present. Hence BM =sqrt(n*(n+2)) = 3.87

B) Since Ni is in +2 oxidation state, the electronic configuration is 4s0 3d8. That means 2 unpaired electrons are present. Hence BM =sqrt(n*(n+2)) = 2.83

C) Since Co is in +3 oxidation state, the electronic configuration is 4s0 3d4. That means 3 unpaired electrons are present. Hence BM =sqrt(n*(n+2)) = 4.90

D) Since Ni is in +2 oxidation state but CN is a strong field ligand, the electronic configuration is 4s0 3d8 with all electrons paired. That means 0 unpaired electrons are present . Hence BM =sqrt(n*(n+2)) = 0