From a pack of 52 cards, we draw one by one, without replacement. If f(n) is the probability that an Ace will appear at the $$n^{th}$$ turn, then

A

$$f(2) = \frac{1}{13} > f(3)$$

B

$$\frac{1}{13} > f(2) > f(3)$$

C

$$f(3) > f(2) > \frac{1}{13}$$

D

$$f(2) = f(3) = \frac{1}{13}$$