Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the odd letter-cluster.

The logic here is

EYC  $$\longrightarrow\ $$ E = 5, Y = 25, C = 3

CUZ $$\longrightarrow\ $$ C = 3, U = 21, Z = 26

DPT $$\longrightarrow\ $$ D = 4, P = 16, T = 20

BDH $$\longrightarrow\ $$ B = 2, D = 4, H = 8

In the letter-clusters EYC, DPT, BDH, the values of all letters are either odd or even.

In CUZ, two letters are odd and one letter is even.

$$\therefore\ $$CUZ is the odd one among the given letter-clusters.

Hence, the correct answer is Option B