Four fair dice $$D_1, D_2, D_3$$ and $$D_4$$ each having six faces numbered 1, 2, 3, 4, 5 and 6 are rolled simultaneously. The probability that $$D_4$$ shows a number appearing on one of $$D_1, D_2$$ and $$D_3$$ is

A

$$\frac{91}{216}$$

B

$$\frac{108}{216}$$

C

$$\frac{125}{216}$$

D

$$\frac{127}{216}$$