Weight of P is twice that of Q. Weight of Q is half of R. Weight of R is 3 times of T. Weight of T is half of S. The weight of Q is greater than the weight of how many persons among P, R, S and T?
Let weight of S = $$100$$ kg
=> T's weight = $$\frac{100}{2}=50$$ kg
=> R's weight = $$3\times50=150$$ kg
=> Q's weight =Â $$\frac{150}{2}=75$$ kg
=> P's weight = $$2\times75=150$$ kg
$$\therefore$$ Weights in descending order : P = R > S > Q > T
$$\therefore$$ Weight of Q is greater than only 1 person.
=> Ans - (A)
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