The interhalogen compound formed from the reaction of bromine with excess of fluorine is a

We need to find what type of interhalogen compound is formed when bromine reacts with excess fluorine, and classify it by its analogous halate type.

When bromine reacts with excess fluorine, it undergoes the reaction $$Br_2 + 5F_2 \rightarrow 2BrF_5$$ resulting in the formation of $$BrF_5$$ (bromine pentafluoride), where bromine is in the +5 oxidation state.

Interhalogen compounds are classified analogous to oxoacid salts based on the oxidation state of the central halogen:

- Hypohalite: +1 oxidation state (like $$XY$$, e.g., $$ClF$$)

- Halite: +3 oxidation state (like $$XY_3$$, e.g., $$ClF_3$$)

- Halate: +5 oxidation state (like $$XY_5$$, e.g., $$BrF_5$$)

- Perhalate: +7 oxidation state (like $$XY_7$$, e.g., $$IF_7$$)

Since $$BrF_5$$ has bromine in the +5 oxidation state, it is classified as a halate.

Hence, the correct answer is Option B.