The area of the circumcircle of a right angle triangle whose sides are given as 2 cm, $$2\sqrt{3}$$ cm and 4 cm, is given by
C which is the length of the hypotenuse of a right angled triangle of a circumcircle passing through the centre of the circumcircle.
Sides are given as 2 cm, $$2\sqrt{3}$$ cm and 4 cm,
Since hypotenuse of a right angled triangle is the longest side i.e c = 4 cm which makes it the diameter of the circumcircle.
Therefore, area of the circumcircle = $$\pi \times R^2 = \pi \times 2^2$$
$$=\pi \times 4 cm^2$$
Option B is correct.
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