Question 42
The base of a triangle is fifth of the base of a parallelogram having the same area as that of the triangle. The ratio of the corresponding heights of the triangle and the parallelogram will be
Solution
The base of a triangle is fifth of the base of a parallelogram having the same area as that of the triangle.
$$h_{t} = $$Height of Triangle
$$h_{p} = $$ Height of Paralellogram
b breadth of parallelogram
Area of triangle = Area of parallelogram
$$\frac{1}{2}\times h_{t}\times \frac{b}{5} = b\times h_{p}$$
$$\Rightarrow \frac{h_{t}}{h_{p}} = \frac{10}{1} $$
Option B is correct.
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