Match the List-I with List-II:
Cations      Group reaction
P $$\to$$ Pb$$^{2+}$$, Cu$$^{2+}$$      H$$_2$$S gas in presence of dilute HCl
Q $$\to$$ Al$$^{3+}$$, Fe$$^{3+}$$      (NH$$_4$$)$$_2$$CO$$_3$$ in presence of NH$$_4$$OH
R $$\to$$ Co$$^{2+}$$, Ni$$^{2+}$$      NH$$_4$$OH in presence of NH$$_4$$Cl
S $$\to$$ Ba$$^{2+}$$, Ca$$^{2+}$$      H$$_2$$S in presence of NH$$_4$$OH

Match the cations with their group reactions in qualitative analysis.

Group II (H$$_2$$S in dilute HCl): Pb$$^{2+}$$, Cu$$^{2+}$$, Bi$$^{3+}$$, Cd$$^{2+}$$, As$$^{3+}$$, Sb$$^{3+}$$, Sn$$^{2+}$$

So P (Pb$$^{2+}$$, Cu$$^{2+}$$) → H$$_2$$S gas in presence of dilute HCl = i

Group III (NH$$_4$$OH in presence of NH$$_4$$Cl): Al$$^{3+}$$, Fe$$^{3+}$$, Cr$$^{3+}$$

So Q (Al$$^{3+}$$, Fe$$^{3+}$$) → NH$$_4$$OH in presence of NH$$_4$$Cl = iii

Group IV (H$$_2$$S in presence of NH$$_4$$OH): Co$$^{2+}$$, Ni$$^{2+}$$, Mn$$^{2+}$$, Zn$$^{2+}$$

So R (Co$$^{2+}$$, Ni$$^{2+}$$) → H$$_2$$S in presence of NH$$_4$$OH = iv

Group V ((NH$$_4$$)$$_2$$CO$$_3$$ in presence of NH$$_4$$OH): Ba$$^{2+}$$, Ca$$^{2+}$$, Sr$$^{2+}$$

So S (Ba$$^{2+}$$, Ca$$^{2+}$$) → (NH$$_4$$)$$_2$$CO$$_3$$ in presence of NH$$_4$$OH = ii

Matching: P→i, Q→iii, R→iv, S→ii

The correct answer is Option D: P→i, Q→iii, R→iv, S→ii.