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Question 43

Match List I with List II:

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Choose the correct answer from the options given below:

Solution

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  • A. Ni+2 has a 3d8 configuration. The strong field CN- ligand forces pairing of the 3d electrons, vacating one 3d orbital. This results in square planar geometry with dsp2 hybridization.
  • B. Ni is in zero oxidation state 3d8 4s2. The extremely strong CO ligand forces the 4s electrons into the 3d orbitals, resulting in a completely filled 3d10 shell. The four CO groups then use the 4s and three 4p orbitals, forming a tetrahedral shape with sp3 hybridization.
  • C. Co+3 has a 3d6 configuration. NH3 acts as a strong field ligand here, causing all six d-electrons to pair up in the lower t2g orbitals. This leaves two 3d orbitals empty for inner orbital octahedral bonding with d2sp3 hybridization.
  • D. Co+3 3d6 encounters F, a weak field ligand that cannot force electron pairing. The electrons remain unpaired, and the complex uses the outer 4d orbitals for bonding. This forms an outer orbital octahedral complex with sp3d2 hybridization.

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