Question 42

The number of different solutions $$(x,y,z)$$ of the equation $$x + y + z = 10$$, where $$x, y$$ and $$z$$ are positive integers, is

Solution

Assume x=a+1, y=b+1, z=c+1

a+1+b+1+c+1=10,

a+b+c=7

The number of non-negative solutions for a, b and c will give the postive integral solution for x,y,z which is $$^{7+3-1}C_{3-1}$$ = $$\ \frac{\ 9\times\ 8}{2}$$ = 36


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