Highest oxidation state of Mn is exhibited in Mn$$_2$$O$$_7$$. The correct statements about Mn$$_2$$O$$_7$$ are
(A) Mn is tetrahedrally surrounded by oxygen atoms
(B) Mn is octahedrally surrounded by oxygen atoms
(C) Contains Mn-O-Mn bridge
(D) Contains Mn-Mn bond.
Choose the correct answer from the options given below

In $$Mn_2O_7$$, manganese is in its highest oxidation state of +7.

Let us analyze the structure of $$Mn_2O_7$$:

(A) Mn is tetrahedrally surrounded by oxygen atoms - CORRECT. Each Mn atom is bonded to four oxygen atoms in a tetrahedral arrangement (three terminal O atoms and one bridging O atom).

(B) Mn is octahedrally surrounded by oxygen atoms - INCORRECT. The coordination around Mn is tetrahedral, not octahedral.

(C) Contains Mn-O-Mn bridge - CORRECT. The two MnO₄ tetrahedra are connected through a Mn-O-Mn bridge (one shared oxygen atom between the two Mn centers).

(D) Contains Mn-Mn bond - INCORRECT. There is no direct Mn-Mn bond. The two Mn atoms are connected through a bridging oxygen atom.

Therefore, the correct statements are A and C only.