Among the given oxides of nitrogen; N$$_2$$O, N$$_2$$O$$_3$$, N$$_2$$O$$_4$$ and N$$_2$$O$$_5$$, the number of compound/(s) having N - N bond is

We need to determine how many of the given nitrogen oxides — N$$_2$$O, N$$_2$$O$$_3$$, N$$_2$$O$$_4$$, and N$$_2$$O$$_5$$ — contain an N-N bond. N$$_2$$O has the structure N=N=O (linear), so it contains an N-N bond.

N$$_2$$O$$_3$$ has the structure O=N-N=O with an additional oxygen on one nitrogen: ON-NO$$_2$$, so it also contains an N-N bond. N$$_2$$O$$_4$$ is the dimer of NO$$_2$$, with structure O$$_2$$N-NO$$_2$$, and it too contains an N-N bond.

N$$_2$$O$$_5$$ has the structure O$$_2$$N-O-NO$$_2$$, where the two nitrogen atoms are connected through an oxygen bridge; there is no direct N-N bond.

N$$_2$$O, N$$_2$$O$$_3$$, and N$$_2$$O$$_4$$ have N-N bonds, which makes three compounds. Hence, the correct answer is Option C.