Question 41

If each of the letters in the English alphabet is assigned odd numerical value beginning with A = 1, B = 3 and so on, what will be the total value of the letters of the word NOMINAL?

Solution

Given that A =1, B=3, C=5..... and so on

so that it is followed expression $$n^{th} alphabet = 2 \times n -1$$

then NOMINAL Value = ?

N = $$ 2 \times 14 -1 = 27 $$

O = $$ 2 \times 15 -1 = 29 $$

M = $$ 2 \times 13 -1 = 25 $$

I = $$ 2 \times 9 -1 = 17 $$

N = $$ 2 \times 14 = 27 $$

A = $$ 2\times 1-1 = 1 $$

L = $$ 2 \times 12 -1 = 23 $$

therefore total value NOMINAL = 27+29+25+17+27+1+23 = 149 Ans

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