[Solved] An organic compound undergoes first-order decomposition. The time taken for its decomposition to \\frac{1}{8} and \\frac{1}{10} of its initial concentration are t_{\\frac{1}{8}} and t_{\\frac{1}{10}} respectively. What is the value of \\frac{[t_{\\frac{1}{8}}]}{[t_{\\frac{1}{10}}]} \\times 10? (take \\log_{10} 2 = 0.3) - - JEE (Advanced) 2012 Paper-1