Question 40

An organic compound undergoes first-order decomposition. The time taken for its decomposition to $$\frac{1}{8}$$ and $$\frac{1}{10}$$ of its initial concentration are $$t_{\frac{1}{8}}$$ and $$t_{\frac{1}{10}}$$ respectively. What is the value of $$\frac{[t_{\frac{1}{8}}]}{[t_{\frac{1}{10}}]} \times 10$$? (take $$\log_{10} 2 = 0.3$$)

Correct Answer: 9

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