Consider two satellites $$S_1$$ and $$S_2$$ with periods of revolution 1hr and 8hr respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite $$S_1$$ to the angular velocity of satellite $$S_2$$ is:

The angular velocity of a satellite is related to its period of revolution by $$\omega = \frac{2\pi}{T}$$.

For satellite $$S_1$$, the period is $$T_1 = 1$$ hr, so $$\omega_1 = \frac{2\pi}{1}$$.

For satellite $$S_2$$, the period is $$T_2 = 8$$ hr, so $$\omega_2 = \frac{2\pi}{8}$$.

Now the ratio of angular velocities is $$\frac{\omega_1}{\omega_2} = \frac{T_2}{T_1} = \frac{8}{1}$$.

So $$\omega_1 : \omega_2 = 8 : 1$$.

Hence, the correct answer is Option A.