In Young's double slit experiment, the fringe width of the interference pattern produced on the screen is 2.4 $$\mu$$m. If the experiment is carried out in another medium having refractive index 1.2, the fringe width will be _______ $$\mu$$m.

fringe width β = λD / d

in a medium of refractive index n, wavelength becomes λ/n

so new fringe width:

$$β'=(λ/n)D/d=β/n$$

given:

$$β=2.4μm$$
$$n=1.2$$

$$β′=\frac{2.4}{1.2}=2μm$$

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