Question 39

Four numbers have been given, out of which three are alike in some manner and one is different. Select the number number that is different from the rest.

Solution

2197 = 13$$^3$$

1331 = 11$$^3$$

1728 = 12$$^3$$

The numbers 2197, 1331, 1728 are perfect cubes of different numbers whereas 2306 is not perfect cube of any number.

$$\therefore\ $$2306 is the different one among the given numbers.

Hence, the correct answer is Option B

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