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Five angles of a hexagon measure $$116^0$$ each. What is the measure of the remaining angle?
We know that the sum of all interior angles of a hexagon is $$720^\circ$$
Given, five angles are $$116^\circ$$ each.
Sum of 5 angles = $$5 \times 116 = 580^\circ$$
Then, Sixth angle = $$720^\circ - 580^\circ = 140^\circ$$
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