Which two signs need to be interchanged to make the following equation correct?
$$96 − 12 \div 6 + 3 \times 5 = 17$$

/ and -

$$96\ \frac{\ 12}{ }\ -\ 6\ +\ 3\times\ 5=17$$

$$8\ -\ 6\ +\ 3\times\ 5=17$$

$$2\ +\ 15=17$$

$$17=17$$

/ and *

$$96\ -\ 12\times\ 6\ +\ 3\ \frac{\ 5}{ }=17$$

$$96\ -72+\ 3\ \frac{\ 5}{ }=17$$

$$24\ +\ 3\ \frac{\ 5}{ }=17$$

$$27\ \frac{\ 5}{ }=17$$

$$5.4=17$$

+ and -

$$96\ +\ 12\ \frac{\ 6}{ }\ -\ 3\times\ 5=17$$

$$108\ \frac{\ 6}{ }\ -\ 3\times\ 5=17$$

$$108\ \frac{\ 6}{ }\ -\ 15=17$$

$$18\ -\ 15=17$$

$$3=17$$

+ and *

$$96\ -\ 12\ \frac{\ 6}{ }\times\ 3\ +\ 5=17$$

$$84\ \frac{\ 6}{ }\times\ 8=17$$

$$14\times\ 8=17$$

$$112=17$$

Hence option A is the correct answer which is L.H.S=R.H.S